Only when the taskAffinity matches the SingleTask startup pattern will the startup activity run on the same task stack as the taskAffinity.
1. Whether the star category matches the product category or not will have different effects on brand trust and goodwill. When selecting spokesmen, enterprises must consider consistency or coincidence with the positioning of products.
锦言被强行嫁给王爷，拥有双世记忆的她，叱咤整个王府。与王爷从互相讨厌到坠入爱河，这一世，锦言与王爷的爱情更甜！
王穷因为王家族亲牵扯上了命案，这几天也忙起来，每天都早早从翰林院回家，帮大伯处理事务。
Source: http://www.sohu.com/a/210022275_171270
新作的主角是一位为了变强而进行着旅行战斗的少年钢银河，主角以战斗陀螺为契机不断地结识新的朋友和面临新的挑战，从中得到历练。从主角的名字和剧情简介来看就知道本片是偏向热血的少年战斗类作品，虽然从题材和类型上预计本作想要在佳作如云的4月新番当中脱颖而出还是有一定难度的，不过届时还是值得我们一探究竟
该剧改编自小说《济公传》，剧中主要角色济颠和尚在历史上确有其人，他以一个穷和尚之姿，笑闹的性情，诙谐的谈吐，游戏于市井小民与达官贵人之中。济公喜爱仗义相助，一次回到天庭，刚好遇上鬼面观阴上天界想偷取无缝天衣，意外造成许多罗汉落入凡间，济公遂下凡寻找诸多罗汉，进而阻止鬼面观阴危害人间。济公凭着自己无边的法术，历经《噬血石敢当》、《乱点鸳鸯谱》、《落难罗汉》、《真假千金》、《佛宝失窃案》、《状告济公》、《广亮大仙》、《真命天子》、《宫中风云》等10个单元，用嘻笑的态度描述济公济困扶危、惩恶劝善的事迹，意在教化世人为德积善，以收寓教于乐，潜移默化之功。
为了说服卡尔拉不要登上飞往伦敦的航班,萨缪尔在机场做出来一个非常浪漫的举动
他躺在草地上睡得香呢。
Public void method2 () {
旺村的元宝被某网站选中参加一档综艺节目，没想到一炮而红。他奇特的人生经历引发了广泛的社会关注，同时也引发了科学界的瞩目。在名利和欲望的驱使之下，郑正、傅负这两位机器人研究领域的科学家相继卷入元宝争夺战中。学生皇甫不惑也不甘寂寞，借机研制出机器人元宝和龙女，一步步将元宝打造成了家喻户晓的明星。但在真正一飞冲天之后，元宝、皇甫不惑等人渐渐迷失了自我。在对名利的追逐中，皇甫、元宝亲历郑正等人被名利怪兽吞噬了本心，酿成悲剧的过程，不约而同地陷入了对生命价值的反思，在充分认识到亲情、友情和爱情的可贵之后，他们最终选择放下名利，回归原本就属于他们的平凡生活。
《倚天屠龙记之魔教教主》，六月一日上映。
Minimum and Maximum Speed Answering Skills
Application scenario of proxy mode:
Yishang was rushed to the hospital, and the policemen ran to the hospital in panic when they learned of it. Yu Ying, who heard the news of Yishang from Fu Ying, finally couldn't help running to find Yishang. Kezi, who has more and more doubts about Qinglan, told his health. Yu Ying hid the flight time from Fan Ren and left home for the airport early in the morning when the patrol called to see her. Xuancha and Yeon-hee came to the seaside to relax. In the distance, the small rate saw the intimacy of the two people.
Independent Attack +44
With everything you like
The above is just a synchronous chain of responsibilities, We let each node function return a specific value "nextSuccessor" synchronously, To indicate whether to pass the request to the next node, we will often encounter AJAX asynchronous requests in our development. After the request is successful, we need to do something so-and-so. At this time, if we apply the above synchronous request again, it will not take effect. Let's understand and use asynchronous responsibility chain to solve this problem. We add another prototype method Chain.prototype.next to the Chain class to manually pass the request to the next node in the responsibility chain.
